Rhode Island gubernatorial election
1814 Rhode Island gubernatorial election![](//upload.wikimedia.org/wikipedia/commons/thumb/f/f3/Flag_of_Rhode_Island.svg/50px-Flag_of_Rhode_Island.svg.png)
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| | | Nominee | William Jones | | | Party | Federalist | | Popular vote | 2,710 | | Percentage | 76.58% | | |
Governor before election William Jones Federalist | Elected Governor William Jones Federalist | |
The 1814 Rhode Island gubernatorial election was held on 6 April 1814 in order to elect the Governor of Rhode Island. Incumbent Federalist Governor William Jones won re-election as he ran unopposed.[1]
General election
On election day, 6 April 1814, incumbent Federalist Governor William Jones won re-election as he ran unopposed, thereby retaining Federalist control over the office of Governor. Jones was sworn in for his fourth term on 7 May 1814.[2]
Results
Rhode Island gubernatorial election, 1814 Party | Candidate | Votes | % |
| Federalist | William Jones (incumbent) | 2,710 | 76.58 |
| | Scattering | 829 | 23.42 |
Total votes | 3,539 | 100.00 |
| Federalist hold |
References