Election in Mississippi
1840 United States presidential election in Mississippi
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← 1836 | October 30 - December 2, 1840 | 1844 → |
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| | | Nominee | William Henry Harrison | Martin Van Buren | | Party | Whig | Democratic | Home state | Ohio | New York | Running mate | John Tyler | none | Electoral vote | 4 | 0 | Popular vote | 19,515 | 17,010 | Percentage | 53.43% | 46.57% | |
County Results Harrison 50-60% 60-70% 70-80% 80-90% | Tie 50% | Van Buren 50-60% 60-70% 70-80% 80-90% | |
President before election Martin Van Buren Democratic | Elected President William Henry Harrison Whig | |
Elections in Mississippi |
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Mayoral elections |
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- 2005
- 2009
- 2013
- 2017
- 2021
- 2025
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Mayoral elections |
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- 2005
- 2009
- 2013
- 2017
- 2021
- 2025
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Mayoral elections |
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- 2005
- 2009
- 2013
- 2017
- 2021
- 2025
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Mayoral elections |
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- 2005
- 2009
- 2013
- 2017
- 2021
- 2025
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The 1840 United States presidential election in Mississippi took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.
Mississippi voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Mississippi by a margin of 6.86%. As of 2020, this is the only presidential election in American history in which Mississippi has voted for a different candidate than Alabama.
Results
References
- ^ "1840 Presidential General Election Results - Mississippi". U.S. Election Atlas. Retrieved December 23, 2013.