1909 Dutch general election
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All 100 seats in the House of Representatives 51 seats needed for a majority | |||||||||||||||||||||||||||||||||||||||||||||
This lists parties that won seats. See the complete results below.
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Part of the Politics series |
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Local government
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General elections were held in the Netherlands on 11 June 1909,[1] with a second round in some constituencies on 23 June.[2] The Anti-Revolutionary Party and the General League of Roman Catholic Electoral Associations emerged as the largest parties, each winning 25 of the 100 seats in the House of Representatives.[3]
Results
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Party | Votes | % | Seats | +/– | |
Anti-Revolutionary Party | 166,270 | 27.90 | 25 | +10 | |
Liberal Union | 106,086 | 17.80 | 20 | – | |
Social Democratic Workers' Party | 82,855 | 13.90 | 7 | 0 | |
General League | 76,087 | 12.77 | 25 | 0 | |
Christian Historical Union | 63,306 | 10.62 | 10 | +2 | |
Free-thinking Democratic League | 54,007 | 9.06 | 9 | –2 | |
Liberal Democratic League | 33,364 | 5.60 | 4 | – | |
Other parties | 13,985 | 2.35 | 0 | 0 | |
Total | 595,960 | 100.00 | 100 | 0 | |
Registered voters/turnout | 843,487 | – | |||
Source: Nohlen & Stöver |
References
- ^ Dieter Nohlen & Philip Stöver (2010) Elections in Europe: A data handbook, p1395 ISBN 978-3-8329-5609-7
- ^ Daniele Caramani (2017). Elections in Western Europe 1815-1996. Springer. p. 704. ISBN 978-1-349-65508-3.
- ^ Nohlen & Stöver, p1412